열역학 솔루션(Thermodynamics: An Engineering Approach)7판

열역학 솔루션(Thermodynamics: An Engineering Approach)7판 열역학 솔루션.zip 목차 Chapter 1 INTRODUCTION AND BASIC CONCEPTS Chapter 2 ENERGY, ENERGY TRANSFER, AND GENERAL ENERGY ANALYSIS Chapter 3 PROPERTIES OF PURE SUBSTANCES Chapter 4 ENERGY ANALYSIS OF CLOSED SYSTEMS Chapter 5 MASS AND ENERGY ANALYSIS OF CONTROL VOLUMES Chapter 6 THE SECOND LAW OF THERMODYNAMICS Chapter 7 ENTROPY Chapter 8 EXERGY – A MEASURE OF WORK POTENTIAL Chapter 9 GAS POWER CYCLES Chapter 10 VAPOR AND COMBINED POWER CYCLES Chapter 11 REFRIGERATION CYCLES Chapter 12 THERMODYNAMIC PROPERTY RELATIONS Chapter 13 GAS MIXTURES Chapter 14 GAS-VAPOR MIXTURES AND AIR CONDITIONING Chapter 15 CHEMICAL REACTIONS Chapter 16 CHEMICAL AND PHASE EQUILIBRIUM Chapter 17 COMPRESSIBLE FLOW 본문 1-7E The weight of a man on earth is given. His weight on the moon is to be determined. Analysis Applying Newtons second law to the weight force gives lbm 5.210lbf 1ft/slbm 174.32ft/s 10.32lbf 21022=⎟⎟⎠⎞⎜⎜⎝⎛⋅⎯→⎯=gWmmgW Mass is invariant and the man will have the same mass on the moon. Then, his weight on the moon will be lbf 35.8=⎟⎠⎞⎜⎝⎛⋅22ft/slbm 174.32lbf 1)ft/s 47.5)(lbm 5.210(mgW 1-8 The interior dimensions of a room are given. The mass and weight of the air in the room are to be determined. Assumptions The density of air is constant throughout the room. Properties The density of air is given to be ρ = 1.16 kg/m3. ROOM AIR 6X6X8 m3 Analysis The mass of the air in the room is kg 334.1=××= =)m 86)(6kg/m (1.1633Vρm Thus, N 3277=⎟⎟⎠⎞⎜⎜⎝⎛⋅22m/skg 1N 1)m/s kg)(9.81 (334.1mgW preparation. If you are a student using this Manual, you are using it without permission. PROPRIETARY MATERIAL. © 2011 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course mVv 2 1 7 3 V (m3) P (kPa) Using the ideal gas equation, 200 K 505.1=⋅KkJ/kg 0769.2)/kgm kPa)(7 (1503111RPTv Since the pressure stays constant, K 216.5=)K 1.505(m 7m 3331122TTVV and the work integral expression gives kJ 600mkPa 1kJ 1m )7kPa)(3 (150)( 33122 1 out,−=⎟⎟⎠⎞⎜⎜⎝⎛⋅−=−∫VVVPdPWb That is, kJ 600=in,bW preparation. If you are a student using this Manual, you are using it without permission. 참고문헌 Yunus A. Cengel, Michael A. Boles McGraw-Hill, 2011 하고 싶은 말 열역학 솔루션, 기계공학과 열역학 응용열역학 과목 솔루션 Thermodynamics: An Engineering Approach)7판 Yunus A. Cengel, Michael A. Boles McGraw-Hill, 2011